The adsorption capacity (expressed by S) of activated carbon is different for different organic gases. Based on a sewage enterprise with 150mg/m3, air volume at 50,000m3/h and 15 hours of work a day, the equilibrium retention of activated carbon is taken as 30% and the time for 1t of activated carbon to reach satiation is
T(d)=m*S/C*10-6(kg/mg)*F*t(15h/d)
m: mass of activated carbon, kg.
S: equilibrium retention, %.
C:total concentration of VOCs, mg/m3.
F:air volume, m3/h.
Then T=1000*0.3/150*10-6*50,000*15=2.67d
That is, 1t of activated carbon under the above conditions, 2.67 days.
